關(guān)于合并同類項(xiàng)100題及答案,合并同類項(xiàng)練習(xí)題及答案這個(gè)問(wèn)題很多朋友還不知道,今天小六來(lái)為大家解答以上的問(wèn)題,現(xiàn)在讓我們一起來(lái)看看吧!
1、例合并同類項(xiàng) (1)(3x-5y)-(6x+7y)+(9x-2y) (2)2a-[3b-5a-(3a-5b)] (3)(6m2n-5mn2)-6(m2n-mn2) 解:(1)(3x-5y)-(6x+7y)+(9x-2y) =3x-5y-6x-7y+9x-2y (正確去掉括號(hào)) =(3-6+9)x+(-5-7-2)y (合并同類項(xiàng)) =6x-14y (2)2a-[3b-5a-(3a-5b)] (應(yīng)按小括號(hào),中括號(hào),大括號(hào)的順序逐層去括號(hào)) =2a-[3b-5a-3a+5b] (先去小括號(hào)) =2a-[-8a+8b] (及時(shí)合并同類項(xiàng)) =2a+8a-8b (去中括號(hào)) =10a-8b (3)(6m2n-5mn2)-6(m2n-mn2) (注意第二個(gè)括號(hào)前有因數(shù)6) =6m2n-5mn2-2m2n+3mn2 (去括號(hào)與分配律同時(shí)進(jìn)行) =(6-2)m2n+(-5+3)mn2 (合并同類項(xiàng)) =4m2n-2mn2 例2.已知:A=3x2-4xy+2y2,B=x2+2xy-5y2 求:(1)A+B (2)A-B (3)若2A-B+C=0,求C。
2、 解:(1)A+B=(3x2-4xy+2y2)+(x2+2xy-5y2) =3x2-4xy+2y2+x2+2xy-5y2(去括號(hào)) =(3+1)x2+(-4+2)xy+(2-5)y2(合并同類項(xiàng)) =4x2-2xy-3y2(按x的降冪排列) (2)A-B=(3x2-4xy+2y2)-(x2+2xy-5y2) =3x2-4xy+2y2-x2-2xy+5y2 (去括號(hào)) =(3-1)x2+(-4-2)xy+(2+5)y2 (合并同類項(xiàng)) =2x2-6xy+7y2 (按x的降冪排列) (3)∵2A-B+C=0 ∴C=-2A+B =-2(3x2-4xy+2y2)+(x2+2xy-5y2) =-6x2+8xy-4y2+x2+2xy-5y2 (去括號(hào),注意使用分配律) =(-6+1)x2+(8+2)xy+(-4-5)y2 (合并同類項(xiàng)) =-5x2+10xy-9y2 (按x的降冪排列) 例3.計(jì)算: (1)m2+(-mn)-n2+(-m2)-(-0.5n2) (2)2(4an+2-an)-3an+(an+1-2an+1)-(8an+2+3an) (3)化簡(jiǎn):(x-y)2-(x-y)2-[(x-y)2-(x-y)2] 解:(1)m2+(-mn)-n2+(-m2)-(-0.5n2) =m2-mn-n2-m2+n2 (去括號(hào)) =(-)m2-mn+(-+)n2 (合并同類項(xiàng)) =-m2-mn-n2 (按m的降冪排列) (2)2(4an+2-an)-3an+(an+1-2an+1)-(8an+2+3an) =8an+2-2an-3an-an+1-8an+2-3an (去括號(hào)) =0+(-2-3-3)an-an+1 (合并同類項(xiàng)) =-an+1-8an (3)(x-y)2-(x-y)2-[(x-y)2-(x-y)2] [把(x-y)2看作一個(gè)整體] =(x-y)2-(x-y)2-(x-y)2+(x-y)2 (去掉中括號(hào)) =(1--+)(x-y)2 (“合并同類項(xiàng)”) =(x-y)2。
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